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Q.

If g(x)=∫0xcos4tdt then g(x+π) equals:

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a

g(x)+g(π)

b

g(x)−g(π)

c

g(x)g(π)

d

g(x)/g(π)

answer is A.

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Detailed Solution

g(x+π)=∫0x+πcos4tdt=∫0πcos4tdt+∫πx+πcos4tdt =g(π)+I1 In I1 , put t=π+u , so that I1=∫0xcos4(π+u)du=∫0xcos4udu=g(x)

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