If g(x)=x2+x−2 and 12gof(x)=2x2−5x+2, then which is not a possible f(x)?
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a
2x−3
b
−2x+2
c
x−3
d
None of these
answer is C.
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Detailed Solution
12(gof)(x)=2x2−5x+2 or 12g[f(x)]=2x2−5x+2∴ {f(x)}2+{f(x)}−2=22x2−5x+2 or f(x)2+f(x)−4x2−10x+6=0∴ f(x)=−1±1+44x2−10x+62 =−1±16x2−40x+252=−1±(4x−5)2 =2x−3 or −2x+2