First slide

Introduction to limits

Question

$If g (x) = \frac{x}{[x]} for x > 2 then lim_{x \to 2 +} \frac{g (x) - g (2)}{x - 2} =$

Moderate

A

-1
B

0
C

$\frac{1}{2}$
D

1

Solution

$\lim_{x \to 2 +} \frac{g (x) - g (2)}{x - 2} = \lim_{x \to 2 +} \frac{x / 2 - 1}{x - 2} = \frac{1}{2} \lim_{x \to 2 +} \frac{x - 2}{x - 2} = \frac{1}{2} .$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App