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If the gradient to the curve xy+ax+by=0 at (1,1) is 2 then a+2b=

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a

−2

b

2

c

−3

d

3

answer is C.

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Detailed Solution

xy+ax+by=0⇒dydx=−y+ax+b Slope at (1,1) is 2⇒−(1+a)1+b=2⇒a+2b=−3

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