First slide
Theory of equations
Question

 If the graph of f(x)=2x3+ax2+bx(a,bN) cuts the x-axis at three distinct points, then minimum value of (a+b) is 

Moderate
Solution

f(x)=2x3+ax2+bx;a,bN=x2x2+ax+b

 Given f(x) cuts x-axis at 3 distinct points then 

2x2+ax+b must have 2 distinct real roots 

 a28b>0 a2>8b

 Since a,bN, minimum value of a+b is 4 when a=3 and b=1

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