If the graph of the function f(x)=ax−1xnax+1 is symmetrical about the y -axis, then n equals
2
23
14
-13
fx=ax-1xnax+1
fx is symmetric about y-axis . Thus , fx =f-x
⇒ax-1xnax+1=a-x-1-xna-x+1
=1-ax-x n1+ax
⇒xn =- -xn
Hence , the value of n which satisfies this relation is -13