Q.
If a > 0 and discriminant of ax2 + 2bx + c is negative, then Δ=abax+bbcbx+cax+bbx+c0 is
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a
+ve
b
(ac−b)2ax2+2bx+c
c
-ve
d
0
answer is C.
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Detailed Solution
Here a > 0 and 4b2 - 4ac < 0, i.e., ac - b2 > 0.∴ ax2+2bx+c>0,∀x∈RNow,Δ=abax+bbcbx+c00−ax2+2bx+c [Operating R3→R3−xR1−R2 =−ax2+2bx+cac−b2 =−(+ve)(+ve)=−ve
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