If a > 0 and Limx→aax−xaxx−aa=−1 then a =
0
1
e
2e
Limit value is 0/0 ,Use L-Hospital rule ddx(ax)=axloga,ddx(xa)=a.xa−1ddx(xx)=xx(1+logx)limx→a axloga-axa-1xx(1+logx)-0=aaloga-aaaa(1+loga)=-1
loga-1=-1-loga
2loga=0
a=1