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If $H_{n} = 1 + \frac{1}{2} + \frac{1}{3} + \dots + \frac{1}{n}$ then value of
$1 + \frac{3}{2} + \frac{5}{3} + \dots + \frac{2 n - 1}{n}$ is

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Hn+n

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detailed solution

Correct option is B

1+32+53+⋯+2n−1n=(2−1)+2−12+2−13+⋯+2−1n=2n−Hn

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If Hn=1+12+13+…+1n then value of 1+32+53+…+2n−1nis

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If $H_{n} = 1 + \frac{1}{2} + \frac{1}{3} + \dots + \frac{1}{n}$ then value of
$1 + \frac{3}{2} + \frac{5}{3} + \dots + \frac{2 n - 1}{n}$ is