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If A=0α00 and A+I50-50A=abcd , the value of a + b + c + d is

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answer is 2.

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A=0α00 ⇒A+I=1α01⇒A+I2=1α011α01=12α01 A+I50=150α01⇒A+I50-50A=1001=abcd a+b+c+d=2

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If A=0α00 and A+I50-50A=abcd , the value of a + b + c + d is