If A=0α00 and A+I50-50A=abcd ,
the value of a + b + c + d is
A=0α00 ⇒A+I=1α01⇒A+I2=1α011α01=12α01 A+I50=150α01⇒A+I50-50A=1001=abcd a+b+c+d=2