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Q.

If (a+ib) =α+iβ,  then  (b+ia)5  is equal to

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a

β+iα

b

α−iβ

c

β−iα

d

−α−iβ

answer is A.

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Detailed Solution

(b+ia)5=i5(a−ib)5=i(α−iβ)                                     =iα−i2β=β+iα
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If (a+ib) =α+iβ,  then  (b+ia)5  is equal to