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If $a + i b = \sum_{k = 1}^{101} i^{k},$ then $(a, b)$ equals

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Correct option is A

Writea+ib=i+i2+i3+i4+i5+i6+i7+i8+i9+…i98+i99+i100+i101

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If a+ib=∑k=1101 ik, then (a, b) equals

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If $a + i b = \sum_{k = 1}^{101} i^{k},$ then $(a, b)$ equals