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If I= π/2π/2cosxcos3xdx then 3I is 

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Correct option is D

Given integralI=∫−π/2π/2 cos⁡x1−cos2⁡xdx=∫−π/2π/2 cos⁡xsin2⁡xdx=∫−π/2π/2 (cos⁡x)|sin⁡x|dx--------(1) Now, sinx=−sin⁡x, if −π/2≤x<0sin⁡x, if 0


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