If I=∫0π2 cos(sinx)dx,J=∫0π2 sin(cosx)dx and K=∫0π2 cosxdx, then
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a
K>I>J
b
J>I>K
c
I>J>K
d
I>K>J
answer is D.
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Detailed Solution
Given that I=∫0π2 cos(sinx)dx,J=∫0π2 sin(cosx)dx,k=∫0π2 cosxdx We know that cos(sinx)>cosx>sin(cosx) for x∈0,π2 since sinx cosx since cos function is decreasing in0,π2 ⇒∫0π2 cos(sinx)dx>∫0π2 cosxdx>∫0π2 sin(cosx)dx⇒I>K>J