Download the app

Questions  

 If I=dx2ax+x23/2, then I is equal to 

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
−x+a2ax+x2+C
b
−1ax+a2ax+x2+C
c
−1a2x+a2ax+x2+C
d
−1a3x+a2ax+x3+C

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is C

Write 2ax+x2=(x+a)2−a2, and put x+a=asec⁡θ, so that dx=asec⁡θtan⁡θdθ∴I=∫asec⁡θtan⁡θa3tan3⁡θdθ=1a2∫cos⁡θsin2θdθ=−1a2sin⁡θ+C=−1a2sec⁡θtan⁡θ+C=−1a2x+a2ax+x2+C


Similar Questions

x2(ax+b)2dx is equal to


whats app icon
phone icon