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If $A^{2} = A$ , the $(I + A)^{4}$ equals

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Correct option is A

As I and A commute, we can apply binomial theorem to expand (I + A)4. We have(I+A)4=I+4A+6A2+4A3+A4.But A3=A2=A,A4=A3=A∴ (I+A)4=I+4A+6A+4A+A=I+15A

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If A2=A, the (I+A)4equals

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If $A^{2} = A$ , the $(I + A)^{4}$ equals