If I1,I2,I3  are the intercepts on x-axis, y-axis, y=x  with respect to x2+y2+4x+2y−20=0  then

x2+y2+4x+2y−20=0 , C=(−2,−1)  , r=4+1+20=5  I1=x−intercept =2g2−c =24+20=224=46  I2=y−intercept =2f2−c =21+20=221=84  d=⊥re distance from 'C'  to x−y=0  =|−2+1|2=12 I3=length 2r2−d2=225−12 =2492 =72 =98 , I3>I1>I2 .