If Δ$$=6i$$−$$3i143i$$−$$1203i=x+iy$$, then

Correct option is 4x = 0, y = 0

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If $Δ = |\begin{array}{ccc} 6 i & - 3 i & 1 \\ 4 & 3 i & - 1 \\ 20 & 3 & i \end{array}| = x + i y$ , then

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x = 3, y = 1

x = 1, y = 3

x = 0, y = 3

x = 0, y = 0

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detailed solution

Correct option is D

Use C2→C2+3iC3 , given determinant = 0+0i= x+ i y ⇒x=0,y=0

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If Δ=6i−3i143i−1203i=x+iy, then

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If $Δ = |\begin{array}{ccc} 6 i & - 3 i & 1 \\ 4 & 3 i & - 1 \\ 20 & 3 & i \end{array}| = x + i y$ , then