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If ${(\frac{1 + i}{1 - i})}^{n} = - 1, n \in N$ then least value of $n$ is

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Correct option is B

Write 1=−i2 in the numerator, to obtain1+i1−i=−i2+i1−i=i(1−i)1−i=i∴ −1=1+i1−i=inThe least value of n is 2.

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If 1+i1−in=−1,n∈N then least value of n is

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If ${(\frac{1 + i}{1 - i})}^{n} = - 1, n \in N$ then least value of $n$ is