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If Δ=6i3iw43iw203iw=x+iy then 

 

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a
x = 3, y = 1
b
x = 1, y = 3
c
x = 0, y = 3
d
x = 0, y = 0

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detailed solution

Correct option is D

We can writeΔ=−3iw6i114−1−120ii=0∴ x=0,y=0


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