First slide

Operations of matrix

Question

If $I = (\begin{array}{ll} 1 0 \\ 0 1 \end{array}), J = (\begin{array}{cc} 0 & 1 \\ - 1 & 0 \end{array})$ and $B = (\begin{array}{cc} \cos θ & \sin θ \\ - \sin θ & \cos θ \end{array})$ then B equals

Easy

A

$(\cos θ) I + (\sin θ) J$
B

$(\sin θ) I + (\cos θ) J$
C

$(\cos θ) I - (\sin θ) J$
D

$- (\cos θ) I + (\sin θ) J$

Solution

$B = (\cos θ) I + (\sin θ) J$

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