First slide
Vector triple product
Question

If a=2i^+j^+k^,b=i^+2j^+2k^,c=i^+j^+2k^ and (1+α)i^+β(1+α)j^+γ(1+α)(1+β)k^  =a×(b×c) then α,β and  γ are

Moderate
Solution

a×(b×c)=(ac)b(ab)c=5(i^+2j^+2k^)6(i^+j^+2k^)(1+α)i^+β(1+α)j^+γ(1+α)(1+β)k^=i^+4j^2k^1+α=1,β=4 and γ(1)(3)=2 γ=23

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App