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If is a square matrix of even order such that , then
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a
A is a skew-symmetric matrix and A is a square
b
A is symmetric matrix and A is a square
c
A is symmetric matrix and A= 0
d
none of these
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Correct option is D
We have,aij=i2−j2∴ aji=j2−i2⇒aij=−aji.Thus, A is a skew-symmetric matrix of even order. We know that the determinant of every skew-symmetric matrix of even order is a perfect square and that of odd order is zero. Hence, option (d) is correctSimilar Questions
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