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$If A = {(a_{i j})}_{4 \times 4}, such that a_{i j} = \{\begin{array}{ll} 2, wheni = j \\ 0, wheni \neq j \end{array}, then \{\frac{\det (adj (adj A))}{7}\} is ( where {.} represents fractional part function}$

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Correct option is A

from given data |A|=24|adj⁡(adj⁡A)|=249=236⇒det⁡(adj⁡(adj⁡A))7=2367=(7+1)127=17

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If A=aij4×4, such that aij=2, wheni =j0, wheni ≠j, then det⁡(adj⁡(adj⁡A))7 is ( where {.} represents fractional part function}

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$If A = {(a_{i j})}_{4 \times 4}, such that a_{i j} = \{\begin{array}{ll} 2, wheni = j \\ 0, wheni \neq j \end{array}, then \{\frac{\det (adj (adj A))}{7}\} is ( where {.} represents fractional part function}$