If $$A=aij3$$×$$3$$ where $$aij=$$$$cos$$⁡(i+j) then

Correct option is 1A is symmetric

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If $A = {(a_{i j})}_{3 \times 3}$ where $a_{i j} = \cos (i + j)$ then

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A is symmetric

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detailed solution

Correct option is A

A=cos⁡2 cos⁡3 cos⁡4cos⁡3 cos⁡4 cos⁡5cos⁡4 cos⁡5 cos⁡6=A′

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If A=aij3×3 where aij=cos⁡(i+j) then

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If $A = {(a_{i j})}_{3 \times 3}$ where $a_{i j} = \cos (i + j)$ then