First slide

Transpose of matrix

Question

If $A = {(a_{i j})}_{3 \times 3}$ where $a_{i j} = \cos (i + j)$ then

Moderate

A

A is symmetric
B

A is skew-symmetric
C

A is a triangular matrix
D

A is a singular matrix

Solution

$A = (\begin{array}{lll} \cos 2 \cos 3 \cos 4 \\ \cos 3 \cos 4 \cos 5 \\ \cos 4 \cos 5 \cos 6 \end{array}) = A^{'}$

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