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 If I=log(cosx)cos2x, then I equals 

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a
tan⁡xlog⁡cos⁡x+tan⁡x−x+C
b
tan⁡xlog⁡cos⁡x−tan⁡x+x2+C
c
tan⁡xlog⁡cos⁡x−cot⁡x+x+C
d
tan⁡xlog⁡cos⁡x+cot⁡x−x+C

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detailed solution

Correct option is A

I=∫sec2⁡xlog⁡cos⁡xdx=tan⁡xlog⁡cos⁡x−∫tanx(−tan⁡x)dx=tan⁡xlog⁡cos⁡x+tan⁡x−x+C


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