If In=∫01 cos−1 xndx then I6−360I2 is given by
6π25−24π23
6π25−120π23
6π25
6π25−4π23
Integrating by parts, we obtain
In=∫01 cos−1 xndx=xcos−1 x01+∫01 ncos−1 xn−1x1−x2dx=n∫01 x1−x2cos−1 xn−1dx=n−1−x2cos−1 xn-101−∫01 (n−1)cos-1 xn-2dx=nπ2n−1−n(n−1)In−2I6=6⋅π25−6.5I4=6⋅π25−304π23−12I2I6−360I2=6⋅π25−120π23