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$If \sum_{i = 1}^{2 n} \cos^{- 1} x_{i} = 0, then \sum_{i = 1}^{2 n} x_{i} is$

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Correct option is B

Since, 0≤cos−1⁡xi≤π,∴cos−1⁡xi=0 for all i ∴xi=1 for all i∴∑i=12n xi=2n

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If ∑i=12n cos−1⁡xi=0, then ∑i=12n xi is

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$If \sum_{i = 1}^{2 n} \cos^{- 1} x_{i} = 0, then \sum_{i = 1}^{2 n} x_{i} is$