Download the app

Questions  

 If In=(logx)ndx, then In+nIn1 is equal to 

a
x(log⁡x)n
b
(xlog⁡x)n
c
(log⁡x)n−1
d
n(log⁡x)n

detailed solution

Correct option is A

In=∫(log⁡x)ndx∴ In−1=∫(log⁡x)n−1dx Now,  In=∫(log⁡x)n⋅1dx =(log⁡x)nx−n∫(log⁡x)n−11xxdx =x(log⁡x)n−n∫(log⁡x)n−1dx⇒   In=x(log⁡x)n−nIn−1∴ In+nIn−1=x(log⁡x)n

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

If In=tannxdx then (n1)In+In2 is equal to


phone icon
whats app icon