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If 1-i is a root of the equation x2-ax+b=0, then b=

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a

-2

b

-1

c

1

d

2

answer is D.

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Detailed Solution

1-i is a root of the equation so x=1-i⇒(x-1)=-i⇒(x-1)2=(-i)2⇒x2-2x+2=0By comparison, a=2, b=2.

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If 1-i is a root of the equation x2-ax+b=0, then b=