If 2+i3 is a root of the equation x2+px+q=0, where p and q are real, then (p,q)=
(-4, 7)
(4, -7)
(4, 7)
(-4, -7)
Since 2+i3 is a root, therefore 2-i3 will be other root. Now sum of the roots =4=-p and product of roots =7=q. Hence (p,q)=(-4, 7).