If ∑i=120 sin−1xi=10π, then ∑i=120 xi is equal to
20
10
0
None of these
Since, −π2<sin−1x≤π2 sin−1x1+sin−1x2+…+sin−1x20=10π sin−1xi contains maximum value i.e. π2. ∴sin−1xi=π2, 1≤i≤20⇒xi=1, 1≤i≤20 Thus, ∑i=120 xi=20