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Q.

If i=−1, then 4+3−12+i32127+5−12+i32124 is equal to

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a

43i

b

2 3 i

c

1 3- i

d

1 3+i

answer is A.

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Detailed Solution

Let ω=−12+i32 then ω3=1z=4+3ω127+5ω124=4+3ω342ω+5ω341ω=4+3ω+5ω=4+8ω=4−4+43i=43i
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