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Q.

If ∑i=118 xi−8=9 and ∑i=118 xi−82=45 , then the standard deviation of x1,x2,…,x18 is

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a

49

b

94

c

32

d

None of these

answer is C.

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Detailed Solution

Let,di=xi−8∴σx2=σd2=118Σdi2−18Σdi2=118×45−9182=52−14=94⇒σx=32
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