If ∑i=15 xi−100=5 and ∑i=15 xi−1002=25, then the standard deviation of observations 2x1+73,2x2+73,2x3+73,2x4+73,2x5+73 is

Given that ∑i=15 xi−100=5 and ∑i=15 xi−1002=25 Standard deviation of observations 2x1+73,2x2+73,2x3+73,2x4+73,2x5+73 is σ2x1+73=2σxi=2∑i=1nxi2n−∑i=1nxin2=2∑i=15xi−10025−∑i=15xi−10052=2255−552=25−1=4