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 If I=5x2+xdx, then I equals 

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a
x+25−x+3sin−1⁡x+23+C
b
x+25−x+7sin−1⁡x+27+C
c
x+25−x+5sin−1⁡x+25+C
d
None of these

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detailed solution

Correct option is B

Putting 2+x=t2, so that dx=2t, we get I=∫7−t2t(2t)dt=2∫7−t2dt=t7−t2+7sin−1⁡t7+C∴I=x+25−x+7sin−1⁡x+27+C


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