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Questions  

If (4+i)(z+z¯)(3+i)(zz¯)+26i=0, then the value of z2 is 

a
13
b
17
c
19
d
11

detailed solution

Correct option is B

Let z=x+iy, then     2(4+i)x−(3+i)2iy+26i=0⇒4x+y=0,x−3y+13=0⇒x=−1,y=4∴|z|2=17

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