First slide
Algebra of complex numbers
Question

If (4+i)(z+z¯)(3+i)(zz¯)+26i=0, then the value of z2 is 

Moderate
Solution

Let z=x+iy, then 

    2(4+i)x(3+i)2iy+26i=04x+y=0,x3y+13=0x=1,y=4|z|2=17

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