If iz3+z2−z+i=0 , then
Rez=0
Imz=0
|z|=1
none of these
iz3+z2−z+i=0⇒iz3−i2z2−(z−i)=0⇒iz2(z−i)−(z−i)=0⇒iz2−1(z−i)=0⇒ z2=1/i or z=i
In any case |z| = 1