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 If A=220211723 and if A313A+kI=0, then k=

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a
2
b
-2
c
-12
d
12

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detailed solution

Correct option is D

We have A3−β1A2+β2A−β3I=0 Where β1=0;β2=−13;β3=−12∴A3−13A−(−12)I=0⇒A3−13A+12I=0 Clearlv k=12


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