First slide
Trigonometric equations
Question

If the inequality sin2x+acosx+a2>1+cosx holds for any xR then the largest negative integral value of a is

Moderate
Solution

sin2x+acosx+a2>1+cosx

Putting X = 0, we have 

    a+a2>2 or     a2+a2>0 or     (a+2)(a1)>0 or     a<2 or a>1

Therefore, the largest negative integral value of a is -3.

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