If the inequality sin2x+acosx+a2>1+cosx holds for any x∈R then the largest negative integral value of a is
-4
-3
-2
-1
sin2x+acosx+a2>1+cosx
Putting X = 0, we have
a+a2>2 or a2+a−2>0 or (a+2)(a−1)>0 or a<−2 or a>1
Therefore, the largest negative integral value of a is -3.