If A is an invertible matrix and B is an orthogonal matrix. of the order same as that of A, then C=A−1BA is

Let B=cos⁡(π/2)sin⁡(π/2)−sin⁡(π/2)cos⁡(π/2)=01−10and A=1    30    1, A−1=1−301Note that B is an orthogonal matrix.C=A−1BA=1−30101−101301=310−1−3Note that C is neither symmetric, nor skew-symmetric and nor-orthogonal.