If it is known that at the point x = 1 two antiderivatives of f(x)=ex differ by 2 The difference of these antiderivatives at x =100 is
e100
100
2
none of these
Let the two antiderivates be ex+C1 and ex+C2
At x=1,C1−C2=2
At x=100 it is e100+C1−e100−C2
=C1−C2=2