If it is known that at the point x = 1 two antiderivatives of f(x)=ex differ by 2 The difference of these antiderivatives at x =100 is

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e100

100

none of these

answer is C.

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Detailed Solution

Let the two antiderivates be ex+C1 and ex+C2At x=1,C1−C2=2At x=100 it is e100+C1−e100−C2=C1−C2=2

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