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Q.

If Jm=∫1e logm⁡xdxthen J8+8J7 is equal to

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a

2

b

e8

c

2e

d

e

answer is D.

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Detailed Solution

Jm=∫1e logm⁡xdx=xlogm⁡x1e−∫1e mxlogm−1⁡xxdx=e−mJm−1So J8+8J7=e
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