Questions
If then the line passes through the fixed point, then that point is
a
1k,1k
b
2k,2k
c
k2,k2
d
k,k
detailed solution
Correct option is D
Substitute ab=k(a+b) in the equation xa+yb=1It implies that bx+ay=abbx+ay=ka+bbx−k+ay−k=0 The equation b(x−k)+a(y−k)=0 is in the form of λ1L1+λ2L2=0, which represents the set of lines passing through the point of intersection of lines L1≡x−k=0 and L2≡y−k=0 The point of intersection of lines is (k,k) Therefore, the fixed point is (k,k)Talk to our academic expert!
Similar Questions
If the lines ax+by+c = 0, bx+cy+a = 0 and cx+ay+b=0 are concurrent then the point of concurrency is
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