If k=sin6x+cos6x, then k belongs to the interval
[7/8,5/4]
[1/2,5/8]
[1/4,1]
none of these
We have,
k=sin6x+cos6x⇒ k=sin2x+cos2xsin4x+cos4x−sin2xcos2x⇒ k=1−3sin2xcos2x⇒ k=1−34sin22x
Now,
0≤34sin22x≤34, for all x
⇒ −34≤−34sin22x≤0, for all x⇒ 1−34≤1−34sin22x≤1, for all x⇒ 14≤1−34sin22x≤1, for all x⇒ 14≤k≤1