If  L=  limx→∞  x+1-ax2+x+3 exists finitely thethe value of a isThe value of L is

L=limx→∞  x+1-ax2+x+2      =limx→∞  x+12-ax2+x+3x+1+ax2+x+3      = limx→∞  1-ax2+x-2x+1+ax2+x=3L  exists   finiely  if 1-a=0    or   a=1∴   L=limx→∞  x-2x+1+x2+x+3           =limx→∞  1-2x1+1x+1+1x+3x          =12L=limx→∞  x+1-ax2+x+2      =limx→∞  x+12-ax2+x+3x+1+ax2+x+3      = limx→∞  1-ax2+x-2x+1+ax2+x=3L  exists   finiely  if 1-a=0    or   a=1∴   L=limx→∞  x-2x+1+x2+x+3           =limx→∞  1-2x1+1x+1+1x+3x          =12