If L= limx→0  1x311+x-1+ax1-bx  exists, then

L= limx→0   1x311+x-1+ax1+bx       =  limx→0  1+bx-1+ax1+xx3   limx→0 11+x1+bx       = limx→0  1+bx-1+ax1+x12x3    = limx→0   1+bx-a+ax1+12x+1212-12!x2+1212-112-23!x3+...x3=      limx→0   1+bx-1+ax1+12x-18x2+116x3+....x3= limx→0   b-12-ax+-a2+18x2+a8-116x2x3Limit   exists,   if   b-12-a=0  and  -18+a2=0∴              a=14 and  b=34∴         L=-132