First slide
Evaluation of definite integrals
Question

If l(m,n)=01tm(1+t)ndt then the expression for l(m,n) in terms of l(m+1,n1) is

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Solution

I(m,n)=1m+1tm+1(1+t)n01

nm+1I(m+1,n1)I(m,n)=2nm+1nm+1I(m+1,n1)

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