If lx+my+n=0 is an equation of the line joining the extremities of a pair of semi-conjugate diameters of t the ellipsex29+y24=1, then 9l2+4m2n2 is equal to
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a
– 1
b
0
c
1
d
2
answer is D.
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Detailed Solution
Let the extremities of a pair of semi-conjugatediameters of the ellipse be P(3cos θ, 2sin θ) Q(3cos α, 2sin α), Cbeing the centre.Then slope of CP× slope ofCQ=−49⇒23tan θ×23tan α=−49⇒1+tan θtan α=0⇒α−θ=π/2⇒ coordinates of Q are (−3sin θ, 2cos θ)equation of PQ is2(sin θ−cos θ)x−3(cos θ+sin θ)y+6=0which represents lx+my+n=0, then l2(sin θ−cos θ)=m−3(cos θ+sin θ)=n6 So 9l2+4m2n2=(sin θ−cos θ)2+(cos θ+sin θ)2=2.