If the length of sides of a right triangle are in AP, then the sines of the acute angle are
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a
35,45
b
23,13
c
5−12,5+12
d
3−12,3+12
answer is A.
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Detailed Solution
Let the sides of the triangle be a−d, a, a+d Where a>d>0.By pythagorus theorem, we have (a+d2)=(a−d)2+a2 here a+d is the hypotenuse⇒ 4ad=a2 ⇒ d=a4We have, sinθ=aa+d= 4d4d+d=45and sin(900−θ)=35